Question

the "friends club" purchased some shuttlecocks and cricket balls. Each Shuttle cock cost Rs.8 and each cricket ball cost Rs.15. In how many different ways could the club have bought the items if it spent a total amount of 769

Answer 1

Let

   x=no. Of shuttlecocks

y= no. of cricket balls

Then eqn 8x+15y=769

Dividing eqn by 8 we get

Rem(8x+15y/8)=rem(769/8)

=>Rem(7y/8)=1

By trial ,y=7 satisfies the above condition and the other values of y can be obtained by adding 8 successively

y=7,15,23,31,39,47,55

But for y>=55,15y>769.

So y <55

The corresponding values of x are 83 ,68,53,38,23,8.

Hence the irems can be purchased in 6.