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Let M be the set of all even numbers from 1 to 25 and all the odd numbers between 26 and 200. If all the elements of M are multiplied, find the number of zeroes at the end of this product.

  1. 22
  2. 18
  3. 23
  4. 21
in Quantitative Aptitude 7.9k points 236 900 1073 1.8k views

2 Answers

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We get a 0, when we multiply 2 and 5 together.

For even numbers from 1 to 25, we get 12 + 6 + 3 = 21 2's. For odd numbers from 26-200 we get 25 + 5 + 1 = 31 5's. So, their multiple will have min(21, 31) = 21 zeroes at end.
8.3k points 55 131 178
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Sir, we can get zero by two cases.

I. When we multiply 2 by 5 and

II. When already there is zero at the end.(like in 10)

So taking forward your solution, we get 21 zero's from I case and two more zero's from II case i.e. from 10 and 20.

Final answer would be =21+2=23.
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