0 votes 0 votes Answer the following question based on the information given below. For three distinct real numbers $x, y$ and $z,$ let $f(x, y, z) = \min(\max(x, y), \max(y, z), \max(z, x))$ $g(x, y, z) = \max(\min(x, y), \min(y, z), \min(z, x))$ $h(x, y, z) = \max(\max(x, y), \max(y, z), \max(z, x))$ $j(x, y, z) = \min(\min(x, y), \min(y, z), \min(z, x))$ $m(x, y, z) = \max(x, y, z)$ $n(x, y, z) = \min(x, y, z)$ Which of the following expressions is necessarily equal to $1?$ $(f(x, y, z) – m(x, y, z))/(g(x, y, z) – h(x, y, z))$ $(m(x, y, z) – f(x, y, z))/(g(x, y, z) – n(x, y, z))$ $(j(x, y, z) – g(x, y, z))/h(x, y, z)$ $(f(x, y, z) – h(x, y, z))/f(x, y, z)$ Quantitative Aptitude cat2000 quantitative-aptitude functions + – go_editor asked May 1, 2016 • edited Apr 14, 2022 by Lakshman Bhaiya go_editor 13.8k points 1.2k views answer comment Share See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Answer A Say (x,y,z)=(1,3,4) f(x,y,z)=3 g(x,y,z)=3 h(x,y,z)=4 j(x,y,z)=1 Now putting value we get the answer srestha answered May 1, 2016 srestha 5.2k points comment Share See 1 comment See all 1 1 comment reply Arjun 8.6k points commented May 3, 2016 reply Share Need to show that other options are false also. Or else, prove f=g and m = h. 0 votes 0 votes Please log in or register to add a comment.