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CAT 2001 | Question: 24

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Let Number of pages=n

The sum of all the page numbers = $\frac{n(n+1)}{2}$

We can quite easily see that for n=44, we have the sum as

$\frac{44*45}{2}$ = 22*45 = 990.

Thus, the page number 10 must have been added twice.

 

Hence (3)10 is the Answer.

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